How to use Macro argument as string literal?
c++, c-preprocessor, string-literals
Solution
Use the preprocessor `#` operator:
#define CALL_DO_SOMETHING(VAR) do_something(#VAR, VAR);
Problem
I am trying to figure out how to write a macro that will pass both a string literal representation of a variable name along with the variable itself into a function. For example given the following function. ``` void do_something(string name, int val) { cout << name << ": " << val << endl; } ``` I would want to write a macro so I can do this: ``` int my_val = 5; CALL_DO_SOMETHING(my_val); ``` Which would print out: `my_val: 5` I tried doing the following: ``` #define CALL_DO_SOMETHING(VAR) do_something("VAR", VAR); ``` However, as you might guess, the VAR inside the quotes doesn't get replaced, but is just passed as the string literal "VAR". So I would like to know if there is a way to have the macro argument get turned into a string literal itself.