progress dialog with asynctask

Question

i have 3 classes and the class called WebServiceCleint class is extending `Asynctask` and in `doInBackgrnd()` i m passing url and i m getting data from webservice. but i m calling this from another class's method called VerifyTeacherId. Now how can i show progress dialog??? where should i write the pg.show and pg.dismiss.??? ``` public class WebServiceClient extends AsyncTask<String, Void, String> { private static final String base_path = "http://www.gdaschools.in/"; protected static final String SLASH = "/"; private ProgressDialog dialog; private Activity activity; public WebServiceClient(Activity activity) { this.activity = activity; this.dialog = new ProgressDialog(activity); } @Override protected void onPreExecute() { this.dialog.setMessage("Progress start"); this.dialog.show(); } @Override protected String doInBackground(String... params) { StringBuffer sb = new StringBuffer(); sb.append(base_path); sb.append(params[0]); HttpRetriever retrieveResponse = new HttpRetriever(); retri…

Accepted Answer

Pass context of your current activity to AsyncTask class and using that context show progress dialog in `onPreExecute()` and dismiss it `onPostExecute()`

```
public  class WebServiceClient extends AsyncTask<String, Void, String>
{
 private static final String base_path = "http://www.gdaschools.in";
 protected static final String SLASH = "/";
 private ProgressDialog dialog;
 private Activity activity;

public WebServiceClient(Activity activity) {
    this.activity = activity;
    this.dialog = new ProgressDialog(activity);
}

@Override
 protected void onPreExecute() {
        this.dialog.setMessage("Progress start");
        this.dialog.show();
    }

@Override
    protected void onPostExecute(final Boolean success) {
        if (this.dialog.isShowing()) {
           this.dialog.dismiss();
        }

.
.
.
```

Code is only for your understanding..

progress dialog with asynctask

Solution

Problem