Scope of new memory in C++
c++, memory-leaks, memory-management
Solution
No. You're making a common beginner mistake. You're not remembering that pointers are just variables that are passed by value unless you ask for a reference or pointer to them. Change the signature of your function to `void func1(int *& ptr)`
Problem
When I try to do the following I get an error saying I'm trying to read or write to protected memory. ``` void func1(int * ptr) { int *ptr_b = new int[5]; ptr = ptr_b; } void main() { int *ptr_a; func1(ptr_a); delete [] ptr_a; } ``` Is this legal?