conversion from derived * to base * exists but is inaccessible
c++, inheritance
Solution
You need:
class d : public c
`class` inheritance is `private` by default.
When you privately inherit from a `class` or a `struct`, you explicitly say, among other things, that direct conversion from a derived type to a base type isn't possible.
Problem
Why does the follwing code produce this error even though c is a struct and has a public inheritance by default?? ``` struct c { protected: int i; public: c(int ii=0):i(ii){} virtual c *fun(); }; c* c::fun(){ cout<<"in c"; return &c(); } class d : c { public: d(){} d* fun() { i = 9; cout<<"in d"<<'\t'<<i; return &d(); } }; int main() { c *cc; d dd; cc = ⅆ cc->fun(); } ```