C++ style and conversion of 0 to size_t(0)
c++, substr
Solution
That is, when I put only 0 is it converted to size_t(0)?
The conversion is implicit since `substr` is:
basic_string substr( size_type pos = 0,
size_type count = npos );
Thus your cast is superfluous.
Problem
Is using `size_t(0)` the same as using `0` in the following code? ``` const string foo = "testing"; const size_t pos = foo.find("i"); string name = foo.substr(size_t(0), pos); ``` That is, when I put only `0` is it converted to `size_t(0)`? If so, is one form preferred over the other? My guess is that `size_t(0)` is the best one to use because it makes the conversion explicit. On the other hand, perhaps some programmers consider `size_t(0)` verbose? I'm guessing in practice no one cares either way.