Find indexes of sequence in list in python

list, python

Solution

With a list comprehension:

>>> [(i, i+len(b)) for i in range(len(a)) if a[i:i+len(b)] == b]
[(3, 6)]

Or with a for-loop:

>>> indexes = []
>>> for i in range(len(a)):
...    if a[i:i+len(b)] == b:
...        indexes.append((i, i+len(b)))
... 
>>> indexes
[(3, 6)]

Problem

I am quite new and I hope it's not too obvious, but I just can't seem to find a short and precise answer to the following problem. I have two lists: ``` a = [2,3,5,2,5,6,7,2] b = [2,5,6] ``` I would like to find when all the indexes of the second list (`b`) are in the first list (`a`), so that I get something like this: indexes of b in a: `3, 4, 5` or `b = a[3:6]`

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