How do I apply a symbol as a function in Scheme?

Question

Is there a way I can apply '+ to '( 1 2 3)? edit: what i am trying to say is that the function i get will be a symbol. Is there a way to apply that? Thanks.

Accepted Answer

```
(apply (eval '+) '(1 2 3))
```

Should do it.

How do I apply a symbol as a function in Scheme?

Solution

Problem