Understanding PIVOT function in T-SQL
pivot, sql-server, sql-server-2008, t-sql
Solution
A `PIVOT` used to rotate the data from one column into multiple columns.
For your example here is a STATIC Pivot meaning you hard code the columns that you want to rotate:
create table temp
(
id int,
teamid int,
userid int,
elementid int,
phaseid int,
effort decimal(10, 5)
)
insert into temp values (1,1,1,3,5,6.74)
insert into temp values (2,1,1,3,6,8.25)
insert into temp values (3,1,1,4,1,2.23)
insert into temp values (4,1,1,4,5,6.8)
insert into temp values (5,1,1,4,6,1.5)
select elementid
, [1] as phaseid1
, [5] as phaseid5
, [6] as phaseid6
from
(
select elementid, phaseid, effort
from temp
) x
pivot
(
max(effort)
for phaseid in([1], [5], [6])
)p
Here is a SQL Demo with a working version.
This can also be done through a dynamic PIVOT where you create the list of columns dynamically and perform the PIVOT.
DECLARE @cols AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX);
select @cols = STUFF((SELECT distinct ',' + QUOTENAME(c.phaseid)
FROM temp c
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT elementid, ' + @cols + ' from
(
select elementid, phaseid, effort
from temp
) x
pivot
(
max(effort)
for phaseid in (' + @cols + ')
) p '
execute(@query)
The results for both:
ELEMENTID PHASEID1 PHASEID5 PHASEID6
3 Null 6.74 8.25
4 2.23 6.8 1.5
Problem
I am very new to SQL. I have a table like this: ID TeamID UserID ElementID PhaseID Effort 1 1 1 3 5 6.74 2 1 1 3 6 8.25 3 1 1 4 1 2.23 4 1 1 4 5 6.8 5 1 1 4 6 1.5 And I was told to get data like this ElementID PhaseID1 PhaseID5 PhaseID6 3 NULL 6.74 8.25 4 2.23 6.8 1.5 I understand I need to use PIVOT function. But can't understand it clearly. It would be great help if somebody can explain it in above case.(or any alternatives if any)