In HTML5, can I play the same sound more than once at the same time?

I'm making a game, in which sounds are often played. I noticed that a sound wont play again while it is being played. For example, the player collides with a wall, a "thump" sound is played. But, if the player collides with one wall, and then quickly collides with another wall, only one "thump" sound is played, and I believe that this happens because the first sound didn't finish. Is that true? How should I avoid this? I thought of preloading the sound three times, always playing a different copy of that sound, but this seems rather stupid... SOLVED: Turns out I was right... You need to preload multiple versions of the sound and then circularly play them. THE CODE: ``` var ns = 3; //The number of sounds to preload. This depends on how often the sounds need to be played, but if too big it will probably cause lond loading times. var sounds = []; //This will be a matrix of all the sounds for (i = 0; i < ns; i ++) //We need to have ns different copies of each sound, hence: sounds.push([]); for (i = 0; i < soundSources.length; i ++) for (j = 0; j < ns; j ++) sounds[j].push(new Audio(sources[i])); //Assuming that you hold your sound sauces in a "sources" array, for example ["bla.wav", "smile.dog" "scream.wav"] var playing = []; //This will be our play index, so we know which version has been played the last. for (i = 0; i < soundSources.length; i ++) playing[i] = 0; playSound = function(id, vol) //id in the sounds[i] array., vol is a real number in the [0, 1] interval { if (vol <= 1 && vol >= 0) sounds[playing[id]][id].volume = vol; else sounds[playing[id]][id].volume = 1; sounds[playing[id]][id].play(); ++ playing[id]; //Each time a sound is played, increment this so the next time that sound needs to be played, we play a different version of it, if (playing[id] >= ns) playing[id] = 0; } ```