Reading binary file and looping over each byte
binary, file-io, python
Solution
Python >= 3.8
Thanks to the walrus operator (`:=`) the solution is quite short. We read `bytes` objects from the file and assign them to the variable `byte`
with open("myfile", "rb") as f:
while (byte := f.read(1)):
# Do stuff with byte.
Python >= 3
In older Python 3 versions, we get have to use a slightly more verbose way:
with open("myfile", "rb") as f:
byte = f.read(1)
while byte != b"":
# Do stuff with byte.
byte = f.read(1)
Or as benhoyt says, skip the not equal and take advantage of the fact that `b""` evaluates to false. This makes the code compatible between 2.6 and 3.x without any changes. It would also save you from changing the condition if you go from byte mode to text or the reverse.
with open("myfile", "rb") as f:
byte = f.read(1)
while byte:
# Do stuff with byte.
byte = f.read(1)
Python >= 2.5
In Python 2, it's a bit different. Here we don't get bytes objects, but raw characters:
with open("myfile", "rb") as f:
byte = f.read(1)
while byte != "":
# Do stuff with byte.
byte = f.read(1)
Note that the with statement is not available in versions of Python below 2.5. To use it in v 2.5 you'll need to import it:
from __future__ import with_statement
In 2.6 this is not needed.
Python 2.4 and Earlier
f = open("myfile", "rb")
try:
byte = f.read(1)
while byte != "":
# Do stuff with byte.
byte = f.read(1)
finally:
f.close()
Problem
In Python, how do I read in a binary file and loop over each byte of that file?