How can I left-pad the string representation of a float?

Question

I'm trying to convert a single precision floating point number into an ascii representation of the four bytes that make it (sign/exponent/mantissa). My current code is: ``` Integer.toString(Float.floatToRawIntBits(f),16); ``` `Float.floatToRawIntBits` makes an integer using the same bytes, and then `Integer.toString` creates the ascii digits in hex form (hence the radix = 16 specified). My problem is that I always need 8 ascii characters plus the optional '-' sign, and `Integer.toString` is not padding with left side zeroes. Can anybody come up with an elegant solution? Thanks.

Accepted Answer

You can use String.format():

```
String.format("%08x", Float.floatToRawIntBits(f))
```

This will zero-pad the result and format it as a hexadecimal number. Details on format strings can be found here.

How can I left-pad the string representation of a float?

Solution

Problem