for loop with multiple conditions in Bash scripting

bash, for-loop

Solution

Sounds like you're talking about the arithmetic for loop.

for ((i = j = 0; i < ${#arrayOne[@]} && j < ${#arrayTwo[@]}; i++, j++)); do
    # Do stuff
done

Which assuming `i` and `j` are either unset or zero is approximately equivalent to:

while ((i++ < ${#arrayOne[@]} && j++ < ${#arrayTwo[@]})); do ...

and slightly more portable so long as you don't care about the values of `i`/`j` after the loop.

Problem

It's been a while since I've done intense bash scripting and I forgot the syntax for doing multiple conditions in a for loop. In C, I'd do: ``` for(var i=0,j=0; i<arrayOne.length && j<arrayTwo.length; i++,j++){ // Do stuff } ``` I've been googling for a while and have only found syntax involving nested for loops, not multiple conditions to one for loop.

Original source