python remove C function body
c, match, python, regex, substitution
Solution
I think you're trying to re-invent a wheel that has already been implemented many times before. If all you want is to extract the signature of each function in a C file, there are much easier ways to do it.
The ctags utility will take care of this for you:
~/test$ ctags -x --c-types=f ./test.c
func1 function 1 ./test.c int func1 (int para) {
func2 function 5 ./test.c int func2 (int para) {
~/test$ # Clean up the output a little bit
~/test$ ctags -x --c-types=f ./test.c | sed -e 's/\s\+/ /g' | cut -d ' ' -f 5-
int func1 (int para) {
int func2 (int para) {
Problem
im looking for way how to remove whole bodies from functions in some C source file. For example I have file with this content: ``` 1. int func1 (int para) { 2. return para; 3. } 4. 5. int func2 (int para) { 6. if (1) { 7. return para; 8. } 9. return para; 10. } ``` I have tried these regex: ``` content = re.sub('(\{[.*]?\})', '', content, flags=re.DOTALL) ``` But there is problem with nested { }. This regex substitute only to first }, so lines 9 and 10 are still in content. I think solution should be in counting { and } brackets and stop substitution when counter is on 0. { is found => counter++, } is found => counter--. But I have no idea how to implement this in python. Can u guys give me a kick?