Trying to replace height and width values in PHP

Question

Trying to replace height="" and width="" values in a string($content) with PHP, i've tried preg replace to no avail, and suggestions on what i'm doing wrong? Sample content would be: ``` $content = ''; ``` Code below: ``` if($type === 'video'){ $s = $content; preg_match_all('~(?|"([^"]+)"|(\S+))~', $s, $matches); foreach($matches[1] as $match){ $newVal = $this->_parseIt($match); preg_replace($match, $newVal, $s); } } ``` Here i just take the match and search for my height and width ``` function _parseIt($match) { $height = "height"; $width = "width"; if(substr($match, 0, 5) === $height){ $pieces = explode("=", $match); $pieces[1] = "\"175\""; $new = implode("=", $pieces); return $new; } if(substr($match, 0, 5) === $width){ $pieces = explode("=", $match); $pieces[1] = "\"285\""; $new = implode("=", $pieces); return $new; } $new = $match; return $new; } ``` There's pr…

Accepted Answer

You can use `preg_replace`. It can take an array of regular expressions that you want to match and an array of replacements. You want to match `width="\d+"` and `height="\d+"`. (If you're parsing arbitrary html, you'll want to extend the regex to match optional whitespace, single quotes, etc.)

```
$newWidth = 285;
$newHeight = 175;

$content = preg_replace(
   array('/width="\d+"/i', '/height="\d+"/i'),
   array(sprintf('width="%d"', $newWidth), sprintf('height="%d"', $newHeight)),
   $content);
```

Trying to replace height and width values in PHP

Solution

Problem