Open file dialog and select a file using WPF controls and C#

c#, openfiledialog, textbox, wpf

Solution

Something like that should be what you need:

private void button1_Click(object sender, RoutedEventArgs e)
{
    // Create OpenFileDialog 
    Microsoft.Win32.OpenFileDialog dlg = new Microsoft.Win32.OpenFileDialog();

    // Set filter for file extension and default file extension 
    dlg.DefaultExt = ".png";
    dlg.Filter = "JPEG Files (*.jpeg)|*.jpeg|PNG Files (*.png)|*.png|JPG Files (*.jpg)|*.jpg|GIF Files (*.gif)|*.gif";

    // Display OpenFileDialog by calling ShowDialog method 
    Nullable<bool> result = dlg.ShowDialog();

    // Get the selected file name and display in a TextBox 
    if (result == true)
    {
        // Open document 
        string filename = dlg.FileName;
        textBox1.Text = filename;
    }
}

Problem

I have a `TextBox` named `textbox1` and a `Button` named `button1`. When I click on `button1` I want to browse my files to search only for image files (type jpg, png, bmp...). And when I select an image file and click Ok in the file dialog I want the file directory to be written in the `textbox1.text` like this: ``` textbox1.Text = "C:\myfolder\myimage.jpg" ```

Original source