how to chop last n bytes of a string in bash string choping?
bash
Solution
If your string is stored in a variable called $str, then this will get you give you the substring without the last 20 digits in bash
${str:0:${#str} - 20}
basically, string slicing can be done using
${[variableName]:[startIndex]:[length]}
and the length of a string is
${#[variableName]}
EDIT: solution using sed that works on files:
sed 's/.\{20\}$//' < inputFile
Problem
for example `qa_sharutils-2009-04-22-15-20-39`, want chop last 20 bytes, and get '`qa_sharutils`'. I know how to do it in sed, but why `$A=${A/.\{20\}$/}` does not work? Thanks!