List assignment to other list
python
Solution
Your first mutates the object, your second rebinds the name.
(`list` that `spy` contains)`[2]=8`
(name called "spy")`= "hello"`
Problem
Is there a reason that assigning a list to another list and changing an item in one reflects the change in both, but changing the entire list of one does not reflect the change in both? ``` a=5 b=a a=3 print b #this prints 5 spy = [0,0,7] agent = spy spy[2]=8 print agent #this prints [0,0,8] spy = [0,0,7] agent = spy spy = "hello" print agent #this prints [0,0,7] ```