Hexadecimal over 7F into String in Java

I need to append some hexadecimal characters to my string. I'm trying this: ``` content += Character.toString((char) Integer.parseInt(Integer.toHexString(originalSize).toString(), 16)); ``` And it's working, but when `originalSize` is over 127 (7F in hex) it returns me two hexadecimal values. For example, doing this: ``` content += Character.toString((char) Integer.parseInt(Integer.toHexString(176).toString(), 16)); ``` The result is: `(content hex numbers) C0 B0` B0 is 176 in hexadecimal, but I don't know how to remove C0. Any suggestions please? Thanks! EDIT: I want to send an string to a device via Bluetooth Low Energy. I have an string like this: "ABCABC". In hexadecimal is `41 42 43 41 42 43`. Now, I want to add the format of this string (because the device is waiting for it), so I add it at the end: `41 42 43 41 42 43 7E 06 02`, where: - `7E`: beggining of the format - `06:` number of chars - `02`: specifical format given by manufacturer. I have the main string and I'm adding this three hexadecimal characters by hand. SOLUTION: Based on Devon_C_Miller answer I found my own solution: ``` contentFormated = new byte[originalSize+3]; for(int i=0;i<originalSize;i++){ contentFormated[i] = content.getBytes()[i]; } contentFormated[originalSize] = 0x7E; contentFormated[originalSize+1] = (byte) 0xB0; contentFormated[originalSize+2] = 0x02; ```