pointer to array c++
arrays, c++, pointers
Solution
The parenthesis are superfluous in your example. The pointer doesn't care whether there's an array involved - it only knows that its pointing to an int
int g[] = {9,8};
int (*j) = g;
could also be rewritten as
int g[] = {9,8};
int *j = g;
which could also be rewritten as
int g[] = {9,8};
int *j = &g[0];
a pointer-to-an-array would look like
int g[] = {9,8};
int (*j)[2] = &g;
//Dereference 'j' and access array element zero
int n = (*j)[0];
There's a good read on pointer declarations (and how to grok them) at this link here: http://www.codeproject.com/Articles/7042/How-to-interpret-complex-C-C-declarations
Problem
What is the following code doing? ``` int g[] = {9,8}; int (*j) = g; ``` From my understanding its creating a pointer to an array of 2 ints. But then why does this work: ``` int x = j[0]; ``` and this not work: ``` int x = (*j)[0]; ```