Converting Javascript function into a PHP function

javascript, php

Solution

Scoping does not work quite like JavaScript; you can't simply refer to `$number` inside your callback function, because it does not have a scope chain.

You either have to make it global (not recommended but simple):

<?php
function doFilter($element) { // this could still be anonymous, but doesn't have to be
   return $element - $GLOBALS['number'] >= 0;
}

function closeRoll( $number ) { 
   $GLOBALS['number'] = $number;
   $rollArray = Array(36, 48, 60, 72);
   $closest = array_filter( $rollArray, 'doFilter' );
   return $closest;   
};
?>

Or you could utilize the `use` operator (an elegant solution):

<?php

function closeRoll( $number ) { 
   $rollArray = Array(36, 48, 60, 72);
   $closest = array_filter( $rollArray, function( $element ) use ($number) {
     return $element - $number >= 0;
   });
   return $closest;   
};

?>

Problem

I am new to PHP and I'm trying to convert a simple Javascript function into a PHP function. So far I know to only convert the variables, I need help with the sort function and array filter. Thanks for any help! ``` var closeRoll = function( number ) { var rollArray = [36, 48, 60, 72]; var closest = rollArray.filter(function(ele){ return ele - number >= 0 }).sort()[0]; return closest; }; ``` My half conversion: ``` function closeRoll( $number ) { $rollArray = Array(36, 48, 60, 72); $closest = array_filter( $rollArray, function temp( $rollArray ) { return $rollArray - $number >= 0; }); //.sort()[0]; return $closest; }; ```

Original source