PHP - How to pass a global variable to a function

Question

I have a function that populates an array that was created before the function is launched. To make the population work, I used 'global' in my function. Everything is working fine with the here below situation: ``` $parameter = 'something'; $listOne = array(); my_function($parameter); function my_function($para) { global $listeOne; ...some code $listeOne[0] = 'john'; $listeOne[1] = 'lugano'; } ``` What I would like is to pass the array that is supposed to be used in the function when calling the function. The idea would be to do something like this: ``` $parameter = 'something'; $listOne = array(); $listTwo = array(); my_function($listOne, $parameter); ...some code my_function($listTwo, $parameter); function my_function($list, $para) { ...some code $list[0] = 'john'; $list[1] = 'lugano'; } ``` In addition according to what I read, using global is maybe not the best thing to do... I saw some people using the & sign somewhere and saying it is better. But I don't get it and not find info…

Accepted Answer

It's called referencing:

```
$listOne = array();

function my_function(&$list, $para) {
     ...some code
     $list[0] = 'john';
     $list[1] = 'lugano';
}
my_function($listOne, $parameter);

print_r($listOne); // array (0 => 'john', 1 => 'lugano');
```

Now the omitted array will be changed.

PHP - How to pass a global variable to a function

Solution

Problem