How do I escape the wildcard/asterisk character in bash?
bash, escaping, shell
Solution
Quoting when setting `$FOO` is not enough. You need to quote the variable reference as well:
me$ FOO="BAR * BAR"
me$ echo "$FOO"
BAR * BAR
Problem
For example: ``` me$ FOO="BAR * BAR" me$ echo $FOO BAR file1 file2 file3 file4 BAR ``` and using the `\` escape character: ``` me$ FOO="BAR \* BAR" me$ echo $FOO BAR \* BAR ``` I'm obviously doing something stupid. How do I get the output `BAR * BAR`?