cin.getline() is skipping an input in C++
c++, cin, getline, string
Solution
This:
cin>>n;
Is reading the number only. It leaves the trailing `'\n'` on the stream.
So your first call to `getline()` is reading an empty line containing just a `'\n'`
It is best not to mix the use of `operator>>` and `std::getline()`. You have to be very careful on whether you have left the newline on the stream. I find it easiest to always read a line at a time from a user. Then parse the line separately.
std::string numnber;
std::getline(std::cin, number);
int n;
std::stringstream numberline(number);
numberline >> n;
Problem
If I use the following code, getline doesn't take the last input(for last iteration of "for" loop, it simply skips it) - ``` int main() { int n; map<string, set<string> > lst; string c,s,c2; cin>>n; for(int i=0;i<n;i++) { getline(cin,c); // here it skips the input for last iteration stringstream ss; ss<<c; bool f=1; while(ss>>s) { if(f) { c2=s; f=0; } else lst[c2].insert(s); } } for (map<string, set<string> >::const_iterator ci = lst.begin(); ci != lst.end(); ++ci) { cout<< (*ci).first <<" "<< (*ci).second.size() <<endl; } } ``` To get rid of it, I put cin.ignore() after getline. Now its taking all the inputs but I'm facing a new issue - ``` #include<iostream> #include<string> #include<map> #include<set> #include<sstream> #include<algorithm> using namespace std; int main() { int n; map<string, set<string> > lst; string c,s,c2; cin>>n; for(int i=0;i<n;i++) { getline(cin,c); cin.ignore(); stringstream ss; ss<<c; bool f=1; while(ss>>s) { if(f) { c2=s; f=0; } else lst[c2].insert(s); } } for (map<string, set<string> >::const_iterator ci = lst.begin(); ci != lst.end(); ++ci) { cout<< (*ci).first <<" "<< (*ci).second.size() <<endl; } } ``` The new issue is that while taking c2, first character of string gets removed. For example, if I give "England Jane Doe" as input to getline, in c2 I'll get "ngland". How to get rid of this issue now?