How to extract a string from double quotes?

double-quotes, php, preg-match, preg-match-all, string

Solution

As long as the format stays the same you can do this using a regular expression. `"([^"]+)"` will match the pattern

- Double-quote

- At least one non-double-quote

- Double-quote

The brackets around the `[^"]+` means that that portion will be returned as a separate group.

<?php

$str  = 'This is a text, "Your Balance left $0.10", End 0';

//forward slashes are the start and end delimeters
//third parameter is the array we want to fill with matches
if (preg_match('/"([^"]+)"/', $str, $m)) {
    print $m[1];   
} else {
   //preg_match returns the number of matches found, 
   //so if here didn't match pattern
}

//output: Your Balance left $0.10

Problem

I have a string: This is a text, "Your Balance left $0.10", End 0 How can I extract the string in between the double quotes and have only the text (without the double quotes): Your Balance left $0.10 I have tried `preg_match_all()` but with no luck.

Original source