AND/OR in Python?
logic, python
Solution
As Matt Ball's answer explains, `or` is "and/or". But `or` doesn't work with `in` the way you use it above. You have to say `if "a" in someList or "á" in someList or...`. Or better yet,
if any(c in someList for c in ("a", "á", "à", "ã", "â")):
...
That's the answer to your question as asked.
Other Notes
However, there are a few more things to say about the example code you've posted. First, the chain of `someList.remove... or someList remove...` statements here is unnecessary, and may result in unexpected behavior. It's also hard to read! Better to break it into individual lines:
someList.remove("a")
someList.remove("á")
...
Even that's not enough, however. As you observed, if the item isn't in the list, then an error is thrown. On top of that, using `remove` is very slow, because every time you call it, Python has to look at every item in the list. So if you want to remove 10 different characters, and you have a list that has 100 characters, you have to perform 1000 tests.
Instead, I would suggest a very different approach. Filter the list using a `set`, like so:
chars_to_remove = set(("a", "á", "à", "ã", "â"))
someList = [c for c in someList if c not in chars_to_remove]
Or, change the list in-place without creating a copy:
someList[:] = (c for c in someList if c not in chars_to_remove)
These both use list comprehension syntax to create a new list. They look at every character in `someList`, check to see of the character is in `chars_to_remove`, and if it is not, they include the character in the new list.
This is the most efficient version of this code. It has two speed advantages:
- It only passes through `someList` once. Instead of performing 1000 tests, in the above scenario, it performs only 100.
- It can test all characters with a single operation, because `chars_to_remove` is a `set`. If it `chars_to_remove` were a `list` or `tuple`, then each test would really be 10 tests in the above scenario -- because each character in the list would need to be checked individually.
Problem
I know that the `and` and `or` expressions exist in python, but is there any `and/or` expression? Or some way to combine them in order to produce the same effect as a `and/or` expression? my code looks something like this: ``` if input=="a": if "a" or "á" or "à" or "ã" or "â" in someList: someList.remove("a") or someList.remove("á") or someList.remove("à") or someList.remove("ã") or someList.remove("â") ``` with this, I mean that if the user inputs "a" and any type of "a" is included in a previously defined list, can I have all the types of "a" removed from a given list? python tells me that there is a problem in: ``` someList.remove("a") or someList.remove("á") or someList.remove("à") or someList.remove("ã") or someList.remove("â") ``` he tells me: `ValueError: list.remove(x): x not in list`