decltype for member functions
c++, c++11, decltype
Solution
I'm not quite sure what you want, but it seems `mygetter` is supposed to be simply any object of type `Getter`. Use `std::declval` to obtain such an object without anything else (you can only use it for type deduction)
typedef decltype(std::declval<Getter>().get()) gotten_t;
Problem
How can I get the return type of a member function in the following example? ``` template <typename Getter> class MyClass { typedef decltype(mygetter.get()) gotten_t; ... }; ``` The problem, of course, is that I don't have a "mygetter" object while defining MyClass. What I'm trying to do is: I'm creating a cache that can use, as it's key, whatever is returned by the getter.