Segmentation Fault in strcpy()
c, segmentation-fault, strcpy
Solution
Your typedef defines `Truck` as a `struct struck *`, i.e. a pointer. So it's size will be `4` or `8` depending on the architecture and not the size of the struct
Use `sizeof(*Truck)` to get the actual size of the struct.
You also need to allocate memory for the characters. The easiest way would be using `strdup()`.
Truck CTruck(const char* id, const char* mat, int value, const char* place) {
Truck nT = malloc(sizeof (*Truck));
nT->value = value;
nT->id = strdup(id);
nT->mat = strdup(mat);
nT->place = strdup(place);
return nT;
}
However, I would suggest changing your typedef so it's an alias for the struct, not for a pointer to it:
typedef struct {
char* id;
char* mat;
int value;
char* place;
} Truck;
In your function you then use this:
Truck *nT = malloc(sizeof(Truck));
Problem
I have a basic structure like this ``` typedef struct struck { char* id; char* mat; int value; char* place; } *Truck; ``` And afunction like this which creates a new "instance" of that struct: ``` Truck CTruck(char* id, char* mat, int value, char* place) { Truck nT = (Truck) malloc(sizeof (Truck)); nT->value = value; strcpy(nT->id, id); strcpy(nT->mat, mat); strcpy(nT->place, place); return nT; } ``` I'm getting an error in the first `strcpy`. It compiles without problem.