Notice: Undefined property - how do I avoid that message in PHP?
null, php-5.3, properties
Solution
The function `isset` should do exactly what you need.
PHP: isset - Manual
Example:
$parts = (isset($structure->parts) ? $structure->parts : false);
Problem
Hello I am making this call: ``` $parts = $structure->parts; ``` Now $structure only has parts under special circumstances, so the call returns me null. Thats fine with me, I have a if($parts) {...} later in my code. Unfortunately after the code finished running, I get this message: Notice: Undefined property: stdClass::$parts in ... How can I suppress this message?