For loop for second items in list of lists only. (python)
coding-style, for-loop, nested-lists, python
Solution
You could hack a generator expression
def mymethod():
return [[1,2,3,4],
[1,2,3,4],
[1,2,3,4],
[1,2,3,4]]
mylist = mymethod()
for thing in (i[1] for i in mylist):
print thing
# this bit is meant to be outside the for loop,
# I mean it to represent the last value thing was in the for
if thing:
print thing
Problem
What I have is something like this ``` def mymethod(): return [[1,2,3,4], [1,2,3,4], [1,2,3,4], [1,2,3,4]] mylist = mymethod() for _, thing, _, _ in mylist: print thing # this bit is meant to be outside the for loop, # I mean it to represent the last value thing was in the for if thing: print thing ``` What I want what I want to do is avoid the dummy variables, is there a smarter way to do this than ``` for thing in mylist: print thing[1] ``` because then i would have to use `thing[1]` any other time I needed it, without assigning it to a new variable and then things are just getting messy. newish to python so sorry if I'm missing something obvious