How to use a variable defined inside one function from another function?

function, python, variables

Solution

One approach would be to make `oneFunction` return the word so that you can use `oneFunction` instead of `word` in `anotherFunction` :

def oneFunction(lists):
    category = random.choice(list(lists.keys()))
    return random.choice(lists[category])

    
def anotherFunction():
    for letter in oneFunction(lists):              
        print("_", end=" ")

Another approach is making `anotherFunction` accept `word` as a parameter which you can pass from the result of calling `oneFunction`:

def anotherFunction(words):
    for letter in words:              
        print("_", end=" ")
anotherFunction(oneFunction(lists))

And finally, you could define both of your functions in a class, and make `word` a member:

class Spam:
    def oneFunction(self, lists):
        category=random.choice(list(lists.keys()))
        self.word=random.choice(lists[category])

    def anotherFunction(self):
        for letter in self.word:              
            print("_", end=" ")

Once you make a class, you have to instantiate an instance and access the member functions:

s = Spam()
s.oneFunction(lists)
s.anotherFunction()

Problem

If I have this: ``` def oneFunction(lists): category=random.choice(list(lists.keys())) word=random.choice(lists[category]) def anotherFunction(): for letter in word: #problem is here print("_",end=" ") ``` I have previously defined `lists`, so `oneFunction(lists)` works perfectly. My problem is calling `word` in line 6. I have tried to define `word` outside the first function with the same `word=random.choice(lists[category])` definition, but that makes `word` always the same, even if I call `oneFunction(lists)`. I want to have a different `word` every time I call the first function and then the second. Can I do this without defining that `word` outside the `oneFunction(lists)`?

Original source

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