How do I pass undefined vars to functions without E_NOTICE errors?

Question

Pretty simple question really, how do I pass undefined vars to functions without E_NOTICE errors? When passing undefined variables to functions such as isset(), no error is raised, but send the same to your own function and you'll get a Notice: Undefined offset: etc. I have thought of a few reasons to want this today, but my current function is almost a clone of isset except it will check if any of the args are set, rather than all like isset(a,b,c) does. ``` function anyset() { $argc = func_num_args(); $argv = func_get_args(); for ($i = 0; $i < $argc; $i++) if (isset($argv[$i])) return true; else return false; } ``` Now, I have for example a giant 2d array of [x][y], into which values will be placed at random. I need to check the randomized co-ords contains anything "next" to it (x-1,y-1 to x+1,y+1) etc. I do not want to do a loop of 20,000,000 and initialise each variable. I just want to send 9 vars and check if any are already set. ``` while (anyset($items[$x-1][$y-1],$items[$x][$y…

Accepted Answer

You have three options:

- Use isset to handle the logic properly (isset($x) || isset($y) || isset($z))

- Wrap everything in isset() and then have your function check if any of the arguements are true (kind of bleh)

- Use @ to suppress errors (also bleh)

An example of @ would be:

```
function a($a) { } a(@$x);
```

You should remember though that notices exist for a reason. I avoid error suppressing. It seems hacky to me. I would just properly wrap everything in isset(). It's a lot more verbose, but also, in my opinion anyway, more correct.

How do I pass undefined vars to functions without E_NOTICE errors?

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