Numpy bincount() with floats
numpy, python
Solution
You want something like this?
>>> from collections import Counter
>>> w = np.array([0.1, 0.2, 0.1, 0.3, 0.5])
>>> c = Counter(w)
Counter({0.10000000000000001: 2, 0.5: 1, 0.29999999999999999: 1, 0.20000000000000001: 1})
or, more nicely output:
Counter({0.1: 2, 0.5: 1, 0.3: 1, 0.2: 1})
You can then sort it and get your values:
>>> np.array([v for k,v in sorted(c.iteritems())])
array([2, 1, 1, 1])
The output of `bincount` wouldn't make sense with floats:
>>> np.bincount([10,11])
array([0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1])
as there is no defined sequence of floats.
Problem
I am trying to get a bincount of a numpy array which is of the float type: ``` w = np.array([0.1, 0.2, 0.1, 0.3, 0.5]) print np.bincount(w) ``` How can you use bincount() with float values and not int?