Relative file paths in Python packages
package, python, reference, relative-path
Solution
If you want to reference files from the `foo/package1/resources` folder you would want to use the `__file__` variable of the module. Inside `foo/package1/__init__.py`:
from os import path
resources_dir = path.join(path.dirname(__file__), 'resources')
Problem
How do I reference a file relatively to a package's directory? My directory structure is: ``` /foo package1/ resources/ __init__.py package2/ resources/ __init__.py script.py ``` `script.py` imports packages `package1` and `package2`. Although the packages can be imported by any other script on the system. How should I reference resources inside, say, `package1` to ensure it would work in case `os.path.curdir` is arbitrary?