PyArg_ParseTuple default argument

If I have the following function and the optional argument `myobj` is not passed, does `myobj` remain `NULL` or is it set to `Py_None`? ``` static PyObject * myfunc(PyObject * self, PyObject * args) { PyObject * myobj = NULL; if (!PyArg_ParseTuple(args, "|O", &myobj)) { return NULL; } // ... } ``` According Parsing arguments and building values, `|` Indicates that the remaining arguments in the Python argument list are optional. The C variables corresponding to optional arguments should be initialized to their default value — when an optional argument is not specified, PyArg_ParseTuple() does not touch the contents of the corresponding C variable(s). Does this apply to `PyObject *`s? It's obviously a pointer that exists in C so one could say it's a C variable, but it's a pointer to a python object so one could also say it does not count as a C variable.