Why does this implementation of izip() not work?
python
Solution
The reason your implementation does not work is because the `StopIteration` exception caused by one of the iterables being exhausted is thrown inside a generator expression. It will only terminate the generator expression, not the enclosing generator function.
Problem
To better understand Python's generator I'm trying to implement facilities in the `itertools` module, and get into trouble with `izip`: ``` def izip(*iterables): its = tuple(iter(it) for it in iterables) while True: yield tuple(next(it) for it in its) # ERROR # yield tuple(map(next, its)) # OK ``` My code uses the ERROR line, and the reference implementation (given in the manual) uses the OK line, not considering other tiny differences. With this snippet: ``` for x in izip([1, 2, 3], (4, 5)): print x ``` My code outputs: ``` (1, 4) (2, 5) (3,) () () ... # indefinite () ``` , while the expected output is: ``` (1, 4) (2, 5) ``` What's wrong with my code, please?