Is there a Python equivalent of range(n) for multidimensional ranges?

iteration, numpy, python, range

Solution

In numpy, it's `numpy.ndindex`. Also have a look at `numpy.ndenumerate`.

E.g.

import numpy as np
for x, y in np.ndindex((3,2)):
    print(x, y)

This yields:

0 0
0 1
1 0
1 1
2 0
2 1

Problem

On Python, range(3) will return [0,1,2]. Is there an equivalent for multidimensional ranges? ``` range((3,2)) # [(0,0),(0,1),(1,0),(1,1),(2,0),(2,1)] ``` So, for example, looping though the tiles of a rectangular area on a tile-based game could be written as: ``` for x,y in range((3,2)): ``` Note I'm not asking for an implementation. I would like to know if this is a recognized pattern and if there is a built-in function on Python or it's standard/common libraries.

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