Django templates: accessing the previous and the following element of the list

django, django-templates, python

Solution

You could write a custom template filter for `next` and `previous`:

def next(value, arg):
    try:
        return value[int(arg)+1]
    except:
        return None

and in the template:

{% for ... %}
  {% with list|next:forloop.counter0 as next %}
    {% if next.is_hidden %}
    ...
    {% endif %} 
  {% endwith %}
{% endfor %}

but like others have said, there are probably more elegants solutions doing this via your view

Problem

I am rather new to django templates and have an impression that I have not understood some basics. I have a list of elements and I need to render an element of the list based on conditions against the the previous and the next elements (in case the following or the previous elements are hidden, I need to mark the current element as border element). How can I reference the previous and the following elements within a `for` loop in Django templates?

Original source