Powershell pass variable to start-job
powershell, start-job, variables
Solution
Use the `-ArgumentList` parameter on `Start-Job` e.g.:
Start-Job -Scriptblock {param($p) "`$p is $p"} -Arg 'Server1'
In your case:
$pingblock = {param($servername) pathping $servername | Out-File C:\...\ServerPing.txt}
Start-Job $pingblock -Arg Server1
Problem
within powershell I'd like to learn the best way to call a variable to a start job so I don't have to edit the script for each server as it will be specific based on the client I've placed my script on. ``` $Servername = 'Server1' $pingblock = { pathping $servername | Out-File C:\client\PS\ServerPing.TXT } start-job $pingblock ``` when I run my code above I just get a file with the help as if I forgot the specify the $servername.