% (mod) explanation
c#, math, modulo, operators
Solution
As explained in the comments, the different behaviour is by design. The different languages just ascribe different meanings to the `%` operator.
You ask:
How can I use modulus operator in C#?
You can define a modulus operator yourself that behaves the same way as the Python `%` operator:
int mod(int a, int n)
{
int result = a % n;
if ((result<0 && n>0) || (result>0 && n<0)) {
result += n;
}
return result;
}
Problem
Today I was writing a program in C#, and I used % to calculate some index... My program didn't work, so I debugged it and I realized that "%" is not working like in other program languages that I know. For example: In Python `%` returns values like this: ``` for x in xrange (-5, 6): print x, "% 5 =", x % 5 -5 % 5 = 0 -4 % 5 = 1 -3 % 5 = 2 -2 % 5 = 3 -1 % 5 = 4 0 % 5 = 0 1 % 5 = 1 2 % 5 = 2 3 % 5 = 3 4 % 5 = 4 5 % 5 = 0 ``` In C#: ``` for (int i = -5; i < 6; i++) { Console.WriteLine(i + " % 5 = " + i % 5); } -5 % 5 = 0 -4 % 5 = -4 -3 % 5 = -3 -2 % 5 = -2 -1 % 5 = -1 0 % 5 = 0 1 % 5 = 1 2 % 5 = 2 3 % 5 = 3 4 % 5 = 4 5 % 5 = 0 ``` Did I do something wrong or is `%` not working like it should?