GDB is not displaying hexadecimal values for stack
c, c++, gdb, hex
Solution
You're probably mistyping your command:
Format letters are o(octal), x(hex), d(decimal), u(unsigned decimal), t(binary), f(float), a(address), i(instruction), c(char) and s(string).
You should use this command for hex output: `x /48x $esp`
Problem
I'm trying to have GDB display the hexadecimal values for the stack, so I used the command `x /48b $esp`, which is a command that I saw on the Internet that should show the hexdecimal values for 48 bytes on the stack starting at the location pointed to by the stack pointer. However, when I do this command I get integer values (some negative instead). An example is show below: ``` (gdb) x /48b $esp 0xbffff200: 40 -14 -1 -65 24 -114 4 8 0xbffff208: 123 0 0 0 0 0 0 0 0xbffff210: 16 0 0 0 -3 -112 17 0 0xbffff218: -18 64 27 0 -1 -1 -1 -1 0xbffff220: 88 40 19 0 45 -9 17 0 0xbffff228: 38 38 -64 -14 -1 -65 -64 -14 ``` I've had this command work before (as far as I know it was the exact same command), however all of a sudden it seems not to be working. Any ideas?