Working with lots of data and lots of rasters in R?

large-files, memory-management, r, raster, spatial

Solution

I would do the extract one raster file at a time, and append the results to file as you go.

I cheat making a list of matrices, but since raster can take a filename or a matrix (amongst other things) and you can index with "[[" on a character vector it should work pretty much the same in your case.

files <- list(volcano, volcano * 2, volcano * 3)
library(sp)
SP <- SpatialPoints(structure(c(0.455921585146703, 0.237608166502031, 0.397704673508124, 0.678393354622703, 0.342820219769366, 0.554888036966903, 0.777351335399613, 0.654684656824567), .Dim = c(4L, 2L)))

library(raster)
for (i in seq_len(length(files))) {

    r <- raster(files[[i]])
    e <- extract(r, SP)
    ## print(e)  ## print for debugging
    write.table(data.frame(file = i, extract = e),"cellSummary.csv", col.names = i == 1, append = i > 1, sep = ",", row.names = FALSE)
}

Problem

G'day, I am working with a large dataset with ~125,000 lon/lat locations with date, for species presence/absence records. For at each location I want to work out what the weather was like at each location on the date and during the 3mths prior to the date. To do this I have downloaded daily weather data for a given weather variable (e.g., max temperature) during the 5yr period the data was taken. I have a total of 1,826 raster files, all between 2-3mb. I had planned to stack all raster files, then extract a value from every raster (1,826) for each point. This would produce a massive file I could use to search for the dates I need. This is, however, not possible because I can't stack that many rasters. I tried splitting the rasters into stacks of 500, this works, but the files it produces are about 1Gb and very slow (rows, 125,000; columns, 500). Also, when I try to bring all of these files into R to create a big data frame it doesn't work. I would like to know if there is a way to work with this amount of data in R, or if there is a package that I could use to help. Could I use a package like ff? Does anyone have any suggestions for a less power intensive method to do what I want to do? I have thought about something like a lapply function, but have never used one before and am not really sure where to begin. Any help would be really great, thanks in advance for your time. The code I am currently using without success is below. Kind regards, Adam ``` library(raster) library(rgdal) library (maptools) library(shapefiles) # To create weather data files, first set the working directory to the appropriate location (i.e., maxt) # list of raster weather files files<- list.files(getwd(), pattern='asc') length(files) memory.size(4000) memory.limit(4000) # read in lon/lat data X<-read.table(file.choose(), header=TRUE, sep=',') SP<- SpatialPoints(cbind(X$lon, X$lat)) #separate stacks into mannageable sizes s1<- stack(files[1:500]) i1 <- extract( s1,SP, cellnumbers = True, layer = 1, nl = 500) write.table(i1, file="maxt_vals_all_points_all_dates_1.csv", sep=",", row.names= FALSE, col.names= TRUE) rm(s1,i1) s2<- stack(files[501:1000]) i2 <- extract( s2,SP, cellnumbers = True, layer = 1, nl = 500) write.table(i2, file="maxt_vals_all_points_all_dates_2.csv", sep=",", row.names= FALSE, col.names= TRUE) rm(s2,i2) s3<- stack(files[1001:1500]) i3 <- extract( s3,SP, cellnumbers = True, layer = 1, nl = 500) write.table(i3, file="maxt_vals_all_points_all_dates_3.csv", sep=",", row.names= FALSE, col.names= TRUE) rm(s3,i3) s4<- stack(files[1501:1826]) i4 <- extract( s4,SP, cellnumbers = True, layer = 1, nl =325) write.table(i4, file="maxt_vals_all_points_all_dates_4.csv", sep=",", row.names= FALSE, col.names= TRUE) rm(s4,i4) # read files back in to bind into final file !!! NOT WORKING FILES ARE TOO BIG!! i1<-read.table(file.choose(),header=TRUE,sep=',') i2<-read.table(file.choose(),header=TRUE,sep=',') i3<-read.table(file.choose(),header=TRUE,sep=',') i4<-read.table(file.choose(),header=TRUE,sep=',') vals<-data.frame(X, i1, i2, i3 ,i4) write.table(vals, file="maxt_master_lookup.csv", sep=",", row.names= FALSE, col.names= TRUE) ```

Original source