python regular expression match comma
python, regex
Solution
In the second example, you just need to capture (using `()`) everything that follows the ip:
import re
s = "192.168.1.43,Marry,had ,a,alittle,lamb11"
text = re.findall(r"\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3},(.*)", s)[0]
// text now holds the string Marry,had ,a,alittle,lamb11
To find out if the string ends with a digit, you can use the following:
re.match(".*\d$", process_str)
That is, you match the entire string (`.*`), and then backtrack to test if the last character (using `$`, which matches the end of the string) is a digit.
Problem
In the following string,how to match the words including the commas -- ``` process_str = "Marry,had ,a,alittle,lamb" import re re.findall(r".*",process_str) ['Marry,had ,a,alittle,lamb', ''] ``` -- ``` process_str="192.168.1.43,Marry,had ,a,alittle,lamb11" import re ip_addr = re.findall(r"\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}",l) re.findall(ip_addr,process_str1) ``` How to find the words after the ip address excluding the first comma only i.e, the outout again is expected to be `Marry,had ,a,alittle,lamb11` In the second example above how to find if the string is ending with a digit.