`val (A) = (3)` is correct, but `val (A,B)=(2,3)` can't be compiled, why?
pattern-matching, scala
Solution
In the second code snippet, it using pattern matching to do assessment.
It is translated to the follow code:
val Tuple(A, B) = Tuple2(2,3)
When Scala is doing pattern matching, variable starts with a upper case in the pattern is considered as an constant value (or singleton Object), so `val (a, b) = (2, 3)` works but not `val (A, B) = (2, 3)`.
BTW, your first code snippet does not using pattern matching, it's just an ordinary variable assignment.
If you using `Tuple1` explicitly, it will have same error.
scala> val Tuple1(Z) = Tuple1(3)
<console>:7: error: not found: value Z
val Tuple1(Z) = Tuple1(3)
Here is some interesting example:
scala> val A = 10
A: Int = 10
scala> val B = 20
B: Int = 20
scala> val (A, x) = (10, 20)
x: Int = 20
scala> val (A, x) = (10, 30)
x: Int = 30
scala> val (A, x) = (20, 20)
scala.MatchError: (20,20) (of class scala.Tuple2$mcII$sp)
at .<init>(<console>:9)
at .<clinit>(<console>)
Problem
``` val A = 3 val (A) = (3) ``` Both correct. But: ``` val (A,B) = (2,3) ``` can't be compiled: ``` scala> val (A,B) = (2,3) <console>:7: error: not found: value A val (A,B) = (2,3) ^ <console>:7: error: not found: value B val (A,B) = (2,3) ^ ``` Why?