Django get url path without using "request.path"
django, http-status-code-404, path, python, url
Solution
The 404 template will be rendered with a request context (unlike the 500 server error template).
Make sure that the `django.core.context_processors.request` context processor is in your `TEMPLATE_CONTEXT_PROCESSORS` setting. Note that it is not included by default.
Once you've done that, the request methods that you mention like `get_full_path` should work.
Problem
I am creating a 404.html page in django which will be called when i raise "Http404" I dont know if 404.html will be passed a "RequestContext" object but can I generate the requested url path without using request variable I tried "request.path" and "request.get_full_path" but they dont work for me. Any help would be appreciated.