Passing all parameters of one function to another? (javascript)
javascript
Solution
Use `Function.prototype.apply(thisArg[, argsArray])`, like so:
b.apply(this, arguments);
Now, `arguments` is an array-like object that has some other properties (like `callee`) apart from its n-index properties. So, you probably ought to use `Array.prototype.slice()` to turn the object into a simple array of arguments (though either will work in modern environments).
b.apply(this, Array.prototype.slice.call(arguments));
See also: `Function.prototype.call()`
Problem
How do you pass all the parameters of one function into another ``` function a(){ arguments.length;// this is 1 // how do I pass any parameter function a receives into another function b(what to put here?); // say pass all parameters function a receives to function b } a('asdf'); // this is okay ``` So if function a receives X number of parameters, each parameter is then passed into function b in the same order. So if a("1", "2"); , b("1", "2");, if a("1", 2, [3]); , b("1", 2, [3]);.