Generate Random Color distinguishable to Humans

javascript, jquery

Solution

You could use a fixed set of colors, such as the ones listed in the jquery.color.js plugin.

List of colors from jquery.color.js plugin:

Colors = {};
Colors.names = {
    aqua: "#00ffff",
    azure: "#f0ffff",
    beige: "#f5f5dc",
    black: "#000000",
    blue: "#0000ff",
    brown: "#a52a2a",
    cyan: "#00ffff",
    darkblue: "#00008b",
    darkcyan: "#008b8b",
    darkgrey: "#a9a9a9",
    darkgreen: "#006400",
    darkkhaki: "#bdb76b",
    darkmagenta: "#8b008b",
    darkolivegreen: "#556b2f",
    darkorange: "#ff8c00",
    darkorchid: "#9932cc",
    darkred: "#8b0000",
    darksalmon: "#e9967a",
    darkviolet: "#9400d3",
    fuchsia: "#ff00ff",
    gold: "#ffd700",
    green: "#008000",
    indigo: "#4b0082",
    khaki: "#f0e68c",
    lightblue: "#add8e6",
    lightcyan: "#e0ffff",
    lightgreen: "#90ee90",
    lightgrey: "#d3d3d3",
    lightpink: "#ffb6c1",
    lightyellow: "#ffffe0",
    lime: "#00ff00",
    magenta: "#ff00ff",
    maroon: "#800000",
    navy: "#000080",
    olive: "#808000",
    orange: "#ffa500",
    pink: "#ffc0cb",
    purple: "#800080",
    violet: "#800080",
    red: "#ff0000",
    silver: "#c0c0c0",
    white: "#ffffff",
    yellow: "#ffff00"
};

The rest is simply picking a random property from a Javascript object.

Colors.random = function() {
    var result;
    var count = 0;
    for (var prop in this.names)
        if (Math.random() < 1/++count)
           result = prop;
    return result;
};

Using `Colors.random()` might get you a human-readable color. I even powered an example below.

(function(){
    Colors = {};
    Colors.names = {
        aqua: "#00ffff",
        azure: "#f0ffff",
        beige: "#f5f5dc",
        black: "#000000",
        blue: "#0000ff",
        brown: "#a52a2a",
        cyan: "#00ffff",
        darkblue: "#00008b",
        darkcyan: "#008b8b",
        darkgrey: "#a9a9a9",
        darkgreen: "#006400",
        darkkhaki: "#bdb76b",
        darkmagenta: "#8b008b",
        darkolivegreen: "#556b2f",
        darkorange: "#ff8c00",
        darkorchid: "#9932cc",
        darkred: "#8b0000",
        darksalmon: "#e9967a",
        darkviolet: "#9400d3",
        fuchsia: "#ff00ff",
        gold: "#ffd700",
        green: "#008000",
        indigo: "#4b0082",
        khaki: "#f0e68c",
        lightblue: "#add8e6",
        lightcyan: "#e0ffff",
        lightgreen: "#90ee90",
        lightgrey: "#d3d3d3",
        lightpink: "#ffb6c1",
        lightyellow: "#ffffe0",
        lime: "#00ff00",
        magenta: "#ff00ff",
        maroon: "#800000",
        navy: "#000080",
        olive: "#808000",
        orange: "#ffa500",
        pink: "#ffc0cb",
        purple: "#800080",
        violet: "#800080",
        red: "#ff0000",
        silver: "#c0c0c0",
        white: "#ffffff",
        yellow: "#ffff00"
    };
    Colors.random = function() {
        var result;
        var count = 0;
        for (var prop in this.names)
            if (Math.random() < 1/++count)
               result = prop;
        return { name: result, rgb: this.names[result]};
    };
    var $placeholder = $(".placeholder");
    $placeholder.click(function(){
        var color = Colors.random();
        $placeholder.css({'background-color': color.rgb});
        $("#color").html("It's " + color.name);
    });
})();
.placeholder {
    width: 150px;
    height: 150px;
    border: 1px solid black;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="placeholder"></div>
<span id="color">Click the square above.</span>

Problem

I am trying to randomly generate a color in hex in javascript. However the colors generated are almost indistinguishable from eachother. Is there a way to improve it? Here is the code I am using: ``` function randomColor(){ var allowed = "ABCDEF0123456789", S = "#"; while(S.length < 7){ S += allowed.charAt(Math.floor((Math.random()*16)+1)); } return S; } ``` I heard something about HSL and HSV color model but can't get it to work in my code.

Original source

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